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fix: show null label if option enabled - formula

pull/7299/head
Pranav C 11 months ago
parent
commit
b7081169c2
  1. 6
      packages/nc-gui/components/virtual-cell/Formula.vue

6
packages/nc-gui/components/virtual-cell/Formula.vue

@ -2,7 +2,7 @@
import { handleTZ } from 'nocodb-sdk'
import type { ColumnType } from 'nocodb-sdk'
import type { Ref } from 'vue'
import { CellValueInj, ColumnInj, computed, inject, renderValue, replaceUrlsWithLink, useBase } from '#imports'
import { CellValueInj, ColumnInj, computed, inject, renderValue, replaceUrlsWithLink, useBase, useGlobal } from '#imports'
// todo: column type doesn't have required property `error` - throws in typecheck
const column = inject(ColumnInj) as Ref<ColumnType & { colOptions: { error: any } }>
@ -11,6 +11,8 @@ const cellValue = inject(CellValueInj)
const { isPg } = useBase()
const { showNull } = useGlobal()
const result = computed(() =>
isPg(column.value.source_id) ? renderValue(handleTZ(cellValue?.value)) : renderValue(cellValue?.value),
)
@ -30,6 +32,8 @@ const { showEditNonEditableFieldWarning, showClearNonEditableFieldWarning, activ
<span>ERR!</span>
</a-tooltip>
<span v-else-if="cellValue === null && showNull" class="nc-null uppercase">{{ $t('general.null') }}</span>
<div v-else class="py-2" @dblclick="activateShowEditNonEditableFieldWarning">
<div v-if="urls" v-html="urls" />

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