Browse Source
Myers' algorithm is the standard way to generate diff scripts in an efficient manner (especially memory-wise). The source contains extensive documentation about the principal ideas of the algorithm. Bug: 291083 Eclipse-CQ: 3559 Change-Id: Id873e7c2c204692cb4a1a05d24b733154b9ed49c Signed-off-by: Johannes Schindelin <johannes.schindelin@gmx.de> Signed-off-by: Shawn O. Pearce <spearce@spearce.org>stable-0.7
Johannes Schindelin
15 years ago
committed by
Shawn O. Pearce
1 changed files with 469 additions and 0 deletions
@ -0,0 +1,469 @@
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/* |
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* Copyright (C) 2008-2009, Johannes E. Schindelin <johannes.schindelin@gmx.de> |
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* Copyright (C) 2009, Johannes Schindelin <johannes.schindelin@gmx.de> |
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* and other copyright owners as documented in the project's IP log. |
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* |
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* This program and the accompanying materials are made available |
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* under the terms of the Eclipse Distribution License v1.0 which |
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* accompanies this distribution, is reproduced below, and is |
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* available at http://www.eclipse.org/org/documents/edl-v10.php
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* |
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* All rights reserved. |
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* |
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* Redistribution and use in source and binary forms, with or |
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* without modification, are permitted provided that the following |
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* conditions are met: |
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* |
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* - Redistributions of source code must retain the above copyright |
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* notice, this list of conditions and the following disclaimer. |
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* |
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* - Redistributions in binary form must reproduce the above |
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* copyright notice, this list of conditions and the following |
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* disclaimer in the documentation and/or other materials provided |
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* with the distribution. |
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* |
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* - Neither the name of the Eclipse Foundation, Inc. nor the |
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* names of its contributors may be used to endorse or promote |
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* products derived from this software without specific prior |
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* written permission. |
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* |
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* THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND |
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* CONTRIBUTORS "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, |
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* INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES |
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* OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE |
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* ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT OWNER OR |
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* CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, |
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* SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT |
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* NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; |
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* LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER |
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* CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, |
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* STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) |
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* ARISING IN ANY WAY OUT OF THE USE OF THIS SOFTWARE, EVEN IF |
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* ADVISED OF THE POSSIBILITY OF SUCH DAMAGE. |
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*/ |
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package org.eclipse.jgit.diff; |
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import java.util.ArrayList; |
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import java.util.Iterator; |
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import java.util.List; |
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import org.eclipse.jgit.util.IntList; |
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public class MyersDiff { |
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protected EditList edits; |
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protected Sequence a, b; |
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public MyersDiff(Sequence a, Sequence b) { |
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this.a = a; |
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this.b = b; |
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calculateEdits(); |
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} |
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public EditList getEdits() { |
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return edits; |
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} |
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// TODO: use ThreadLocal for future multi-threaded operations
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MiddleEdit middle = new MiddleEdit(); |
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protected void calculateEdits() { |
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edits = new EditList(); |
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middle.initialize(0, a.size(), 0, b.size()); |
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if (middle.beginA >= middle.endA && |
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middle.beginB >= middle.endB) |
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return; |
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calculateEdits(middle.beginA, middle.endA, |
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middle.beginB, middle.endB); |
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} |
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protected void calculateEdits(int beginA, int endA, |
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int beginB, int endB) { |
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Edit edit = middle.calculate(beginA, endA, beginB, endB); |
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if (beginA < edit.beginA || beginB < edit.beginB) { |
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int k = edit.beginB - edit.beginA; |
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int x = middle.backward.snake(k, edit.beginA); |
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calculateEdits(beginA, x, beginB, k + x); |
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} |
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if (edit.getType() != Edit.Type.EMPTY) |
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edits.add(edits.size(), edit); |
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// after middle
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if (endA > edit.endA || endB > edit.endB) { |
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int k = edit.endB - edit.endA; |
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int x = middle.forward.snake(k, edit.endA); |
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calculateEdits(x, endA, k + x, endB); |
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} |
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} |
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/** |
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* A class to help bisecting the sequences a and b to find minimal |
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* edit paths. |
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* |
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* As the arrays are reused for space efficiency, you will need one |
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* instance per thread. |
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* |
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* The entry function is the calculate() method. |
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*/ |
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class MiddleEdit { |
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void initialize(int beginA, int endA, int beginB, int endB) { |
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this.beginA = beginA; this.endA = endA; |
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this.beginB = beginB; this.endB = endB; |
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// strip common parts on either end
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int k = beginB - beginA; |
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this.beginA = forward.snake(k, beginA); |
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this.beginB = k + this.beginA; |
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k = endB - endA; |
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this.endA = backward.snake(k, endA); |
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this.endB = k + this.endA; |
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} |
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/* |
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* This function calculates the "middle" Edit of the shortest |
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* edit path between the given subsequences of a and b. |
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* |
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* Once a forward path and a backward path meet, we found the |
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* middle part. From the last snake end point on both of them, |
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* we construct the Edit. |
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* |
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* It is assumed that there is at least one edit in the range. |
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*/ |
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// TODO: measure speed impact when this is synchronized
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Edit calculate(int beginA, int endA, int beginB, int endB) { |
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if (beginA == endA || beginB == endB) |
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return new Edit(beginA, endA, beginB, endB); |
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this.beginA = beginA; this.endA = endA; |
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this.beginB = beginB; this.endB = endB; |
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/* |
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* Following the conventions in Myers' paper, "k" is |
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* the difference between the index into "b" and the |
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* index into "a". |
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*/ |
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int minK = beginB - endA; |
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int maxK = endB - beginA; |
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forward.initialize(beginB - beginA, beginA, minK, maxK); |
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backward.initialize(endB - endA, endA, minK, maxK); |
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for (int d = 1; ; d++) |
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if (forward.calculate(d) || |
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backward.calculate(d)) |
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return edit; |
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} |
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/* |
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* For each d, we need to hold the d-paths for the diagonals |
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* k = -d, -d + 2, ..., d - 2, d. These are stored in the |
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* forward (and backward) array. |
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* |
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* As we allow subsequences, too, this needs some refinement: |
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* the forward paths start on the diagonal forwardK = |
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* beginB - beginA, and backward paths start on the diagonal |
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* backwardK = endB - endA. |
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* |
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* So, we need to hold the forward d-paths for the diagonals |
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* k = forwardK - d, forwardK - d + 2, ..., forwardK + d and |
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* the analogue for the backward d-paths. This means that |
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* we can turn (k, d) into the forward array index using this |
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* formula: |
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* |
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* i = (d + k - forwardK) / 2 |
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* |
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* There is a further complication: the edit paths should not |
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* leave the specified subsequences, so k is bounded by |
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* minK = beginB - endA and maxK = endB - beginA. However, |
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* (k - forwardK) _must_ be odd whenever d is odd, and it |
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* _must_ be even when d is even. |
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* |
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* The values in the "forward" and "backward" arrays are |
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* positions ("x") in the sequence a, to get the corresponding |
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* positions ("y") in the sequence b, you have to calculate |
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* the appropriate k and then y: |
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* |
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* k = forwardK - d + i * 2 |
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* y = k + x |
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* |
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* (substitute backwardK for forwardK if you want to get the |
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* y position for an entry in the "backward" array. |
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*/ |
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EditPaths forward = new ForwardEditPaths(); |
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EditPaths backward = new BackwardEditPaths(); |
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/* Some variables which are shared between methods */ |
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protected int beginA, endA, beginB, endB; |
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protected Edit edit; |
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abstract class EditPaths { |
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private IntList x = new IntList(); |
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private IntList snake = new IntList(); |
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int beginK, endK, middleK; |
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int prevBeginK, prevEndK; |
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/* if we hit one end early, no need to look further */ |
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int minK, maxK; // TODO: better explanation
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final int getIndex(int d, int k) { |
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// TODO: remove
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if (((d + k - middleK) % 2) == 1) |
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throw new RuntimeException("odd: " + d + " + " + k + " - " + middleK); |
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return (d + k - middleK) / 2; |
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} |
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final int getX(int d, int k) { |
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// TODO: remove
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if (k < beginK || k > endK) |
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throw new RuntimeException("k " + k + " not in " + beginK + " - " + endK); |
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return x.get(getIndex(d, k)); |
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} |
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final int getSnake(int d, int k) { |
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// TODO: remove
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if (k < beginK || k > endK) |
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throw new RuntimeException("k " + k + " not in " + beginK + " - " + endK); |
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return snake.get(getIndex(d, k)); |
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} |
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private int forceKIntoRange(int k) { |
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/* if k is odd, so must be the result */ |
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if (k < minK) |
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return minK + ((k ^ minK) & 1); |
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else if (k > maxK) |
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return maxK - ((k ^ maxK) & 1); |
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return k; |
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} |
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void initialize(int k, int x, int minK, int maxK) { |
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this.minK = minK; |
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this.maxK = maxK; |
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beginK = endK = middleK = k; |
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this.x.clear(); |
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this.x.add(x); |
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snake.clear(); |
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snake.add(newSnake(k, x)); |
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} |
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abstract int snake(int k, int x); |
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abstract int getLeft(int x); |
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abstract int getRight(int x); |
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abstract boolean isBetter(int left, int right); |
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abstract void adjustMinMaxK(final int k, final int x); |
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abstract boolean meets(int d, int k, int x, int snake); |
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final int newSnake(int k, int x) { |
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int y = k + x; |
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return x + (endA + 1) * y; |
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} |
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final int snake2x(int snake) { |
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return snake % (endA + 1); |
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} |
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final int snake2y(int snake) { |
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return snake / (endA + 1); |
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} |
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final boolean makeEdit(int snake1, int snake2) { |
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int x1 = snake2x(snake1), x2 = snake2x(snake2); |
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int y1 = snake2y(snake1), y2 = snake2y(snake2); |
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/* |
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* Check for incompatible partial edit paths: |
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* when there are ambiguities, we might have |
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* hit incompatible (i.e. non-overlapping) |
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* forward/backward paths. |
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* |
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* In that case, just pretend that we have |
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* an empty edit at the end of one snake; this |
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* will force a decision which path to take |
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* in the next recursion step. |
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*/ |
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if (x1 > x2 || y1 > y2) { |
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x1 = x2; |
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y1 = y2; |
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} |
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edit = new Edit(x1, x2, y1, y2); |
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return true; |
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} |
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boolean calculate(int d) { |
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prevBeginK = beginK; |
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prevEndK = endK; |
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beginK = forceKIntoRange(middleK - d); |
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endK = forceKIntoRange(middleK + d); |
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// TODO: handle i more efficiently
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// TODO: walk snake(k, getX(d, k)) only once per (d, k)
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// TODO: move end points out of the loop to avoid conditionals inside the loop
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// go backwards so that we can avoid temp vars
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for (int k = endK; k >= beginK; k -= 2) { |
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int left = -1, right = -1; |
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int leftSnake = -1, rightSnake = -1; |
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// TODO: refactor into its own function
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if (k > prevBeginK) { |
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int i = getIndex(d - 1, k - 1); |
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left = x.get(i); |
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int end = snake(k - 1, left); |
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leftSnake = left != end ? |
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newSnake(k - 1, end) : |
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snake.get(i); |
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if (meets(d, k - 1, end, leftSnake)) |
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return true; |
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left = getLeft(end); |
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} |
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if (k < prevEndK) { |
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int i = getIndex(d - 1, k + 1); |
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right = x.get(i); |
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int end = snake(k + 1, right); |
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rightSnake = right != end ? |
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newSnake(k + 1, end) : |
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snake.get(i); |
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if (meets(d, k + 1, end, rightSnake)) |
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return true; |
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right = getRight(end); |
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} |
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int newX, newSnake; |
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if (k >= prevEndK || |
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(k > prevBeginK && |
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isBetter(left, right))) { |
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newX = left; |
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newSnake = leftSnake; |
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} |
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else { |
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newX = right; |
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newSnake = rightSnake; |
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} |
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if (meets(d, k, newX, newSnake)) |
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return true; |
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adjustMinMaxK(k, newX); |
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int i = getIndex(d, k); |
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x.set(i, newX); |
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snake.set(i, newSnake); |
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} |
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return false; |
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} |
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} |
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class ForwardEditPaths extends EditPaths { |
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final int snake(int k, int x) { |
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for (; x < endA && k + x < endB; x++) |
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if (!a.equals(x, b, k + x)) |
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break; |
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return x; |
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} |
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final int getLeft(final int x) { |
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return x; |
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} |
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final int getRight(final int x) { |
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return x + 1; |
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} |
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final boolean isBetter(final int left, final int right) { |
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return left > right; |
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} |
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final void adjustMinMaxK(final int k, final int x) { |
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if (x >= endA || k + x >= endB) { |
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if (k > backward.middleK) |
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maxK = k; |
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else |
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minK = k; |
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} |
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} |
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final boolean meets(int d, int k, int x, int snake) { |
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if (k < backward.beginK || k > backward.endK) |
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return false; |
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// TODO: move out of loop
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if (((d - 1 + k - backward.middleK) % 2) == 1) |
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return false; |
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if (x < backward.getX(d - 1, k)) |
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return false; |
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makeEdit(snake, backward.getSnake(d - 1, k)); |
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return true; |
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} |
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} |
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class BackwardEditPaths extends EditPaths { |
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final int snake(int k, int x) { |
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for (; x > beginA && k + x > beginB; x--) |
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if (!a.equals(x - 1, b, k + x - 1)) |
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break; |
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return x; |
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} |
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final int getLeft(final int x) { |
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return x - 1; |
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} |
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final int getRight(final int x) { |
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return x; |
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} |
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final boolean isBetter(final int left, final int right) { |
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return left < right; |
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} |
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final void adjustMinMaxK(final int k, final int x) { |
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if (x <= beginA || k + x <= beginB) { |
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if (k > forward.middleK) |
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maxK = k; |
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else |
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minK = k; |
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} |
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} |
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final boolean meets(int d, int k, int x, int snake) { |
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if (k < forward.beginK || k > forward.endK) |
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return false; |
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// TODO: move out of loop
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if (((d + k - forward.middleK) % 2) == 1) |
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return false; |
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if (x > forward.getX(d, k)) |
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return false; |
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makeEdit(forward.getSnake(d, k), snake); |
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return true; |
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} |
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} |
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} |
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// debugging (TODO: remove)
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public void print(Sequence s, int begin, int end) { |
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RawText raw = (RawText)s; |
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try { |
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while (begin < end) { |
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System.err.print("" + begin + ": "); |
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raw.writeLine(System.err, begin++); |
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System.err.println(""); |
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} |
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} catch (Exception e) { e.printStackTrace(); } |
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} |
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public void print(int beginA, int endA, int beginB, int endB) { |
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System.err.println("<<<<<<"); |
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print(a, beginA, endA); |
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System.err.println("======"); |
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print(b, beginB, endB); |
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System.err.println(">>>>>>"); |
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} |
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public static void main(String[] args) { |
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if (args.length != 2) { |
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System.err.println("Need 2 arguments"); |
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System.exit(1); |
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} |
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try { |
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RawText a = new RawText(new java.io.File(args[0])); |
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RawText b = new RawText(new java.io.File(args[1])); |
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MyersDiff diff = new MyersDiff(a, b); |
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System.out.println(diff.getEdits().toString()); |
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} catch (Exception e) { |
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e.printStackTrace(); |
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} |
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} |
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} |
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